20x^2-31x-12=0

Solution for 20x^2-31x-12=0 equation:

20x^2-31x-12=0

a = 20; b = -31; c = -12;
Δ = b2-4ac
Δ = -312-4·20·(-12)
Δ = 1921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1921}}{2*20}=\frac{31-\sqrt{1921}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1921}}{2*20}=\frac{31+\sqrt{1921}}{40}
$